Bautista surrendered Raonic’s serve in ‘s-Hertogenbosch

Roberto Bautista said goodbye to the tennis tournament ‘s-Hertogenbosch (Netherlands) – who won in 2014 – was overtaken by the Canadian Milos Raonic, who, driven by his twenty-five straight aces, returned to the match and reached the quarterfinals; where the Australian Alex de Minaur will be measured.

In a duel between two players who were once members of the prestigious part of the circuit, now anchored in the lower part of the classification, the North American achieved victory after three sets (4-6, 6-2 and 7-5) and one hour and 48 minutes of assembly.

Bautista, who has not won the trophy since 2022 and has not reached the final since Adelaide in 2023, fell again against Raonic, whom he has never beaten. The Canadian, now ranked 197th in the ATP rankings, once ranked third in the world, has not bid for a title since losing the Cincinnati Masters 1000 final in 2020.

It was the Spaniard’s sixth loss against Raonic, the second on grass after Queens, in London, in 2016. Bautista has never been able to win against Raonic, whom he has always beaten.

The 33-year-old Canadian of Montenegrin origin will play in the quarterfinals against the first seed, the Australian Alex de Minaur who eliminated Belgian Zizou Bergs 7-5 and 6-4.

The current champion of the tournament, the Dutch Tallon Griekspoor, sixth seed, already has an opponent for the quarterfinals. It will be Australian Aleksandar Vukic who defeated Russian Karen Kachanov in three sets 6-4, 5-7 and 7-6(4).

Americans also prospered Tommy Paulsecond favorite, and Sebastian Korda, seventh, which will face off in search of the semifinals. Korda downed Italian Luca Nardi 7-5, 7-5, and Paul needed a comeback to win his match against Australian Alexei Popyrin 5-7, 7-4, 6-3.